Asked by Doodle
A coffee company wants a new flavor of cajun coffee. how many pounds of coffee worth $10 a pound should be added to 20 pounds of coffee worth $4 a pound to get a mixture worth $5 a pound?
Answers
Answered by
helper
x = lbs of cheaper coffee
10x = value of cheaper coffee
4 = lbs of better coffee
4 * 20 = 80 = value of better coffee
20 + x = lbs of mixture
5(20 + x) = value of mixture
10x + 80 = 5(20 + x)
Solve for x
10x = value of cheaper coffee
4 = lbs of better coffee
4 * 20 = 80 = value of better coffee
20 + x = lbs of mixture
5(20 + x) = value of mixture
10x + 80 = 5(20 + x)
Solve for x
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