Asked by Ochuko
A weight of 40N was attached to the end of a wire during modulus experiment, if the length of the wire is 4m and the diameter is 0.44mm and the extension recorded is 0.30mm. calculate the stress and strain of the wire?. take[Pi=3.142
Answers
Answered by
drwls
The strain is:
epsilon = (extension)/(length)
= 0.30 mm/4000 mm = 7.50*10^-5
The stress is
sigma = (tension force)/wire area)
= 40N/[(3.142)(0.22*10^-3)^2] N/m^2
Finish the calculation.
The value of Young's modulus is
E = (stress)/(strain)= sigma/epsilon
epsilon = (extension)/(length)
= 0.30 mm/4000 mm = 7.50*10^-5
The stress is
sigma = (tension force)/wire area)
= 40N/[(3.142)(0.22*10^-3)^2] N/m^2
Finish the calculation.
The value of Young's modulus is
E = (stress)/(strain)= sigma/epsilon
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