Asked by Angela
calculate the heat released when 166g of water at 23.0 degrees celsius are converted to ice at -10.0 degrees celsius
Answers
Answered by
DrBob222
q1 = heat released to move water @ 23C to zero C.
q1 = mass water x specific heat water x (Tfinal-Tinitial).
q2 = heat released to freeze water @ zero C to ice @ zero C.
q2 = mass water x heat fusion.
q3 = heat released to move ice from zero C to -10C.
q3 = mass ice x specific heat ice x (Tfinal-Tinitial).
Total Q = q1 + q2 + q3
q1 = mass water x specific heat water x (Tfinal-Tinitial).
q2 = heat released to freeze water @ zero C to ice @ zero C.
q2 = mass water x heat fusion.
q3 = heat released to move ice from zero C to -10C.
q3 = mass ice x specific heat ice x (Tfinal-Tinitial).
Total Q = q1 + q2 + q3
Answered by
Lauren
322.5
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