Asked by Anonymous
What is the change in kinetic energy of a baseball thrown at 90 mph compared to one thrown at 45 mph?
it is four times as much right?
it is four times as much right?
Answers
Answered by
MathMate
Yes, four times is correct.
Kinetic energy is calculated according to the formula:
KE = (1/2)mv²
So if v2/v1=90/45=2
KE2/KE1
= (1/2)mv2²/((1/2)mv1²)
= (v2/v1)²
= 4
Kinetic energy is calculated according to the formula:
KE = (1/2)mv²
So if v2/v1=90/45=2
KE2/KE1
= (1/2)mv2²/((1/2)mv1²)
= (v2/v1)²
= 4
Answered by
MathMate
In fact, the "change" is
KE2-KE1
=(1/2)m(v2²-v1²)
=(1/2)m((2*v1)²-v1²)
=3*(1/2)mv1²
I.e. the "change" in KE is three times that of the slower ball.
In fact, I would use the word "difference" and not "change", since the balls are distinct.
KE2-KE1
=(1/2)m(v2²-v1²)
=(1/2)m((2*v1)²-v1²)
=3*(1/2)mv1²
I.e. the "change" in KE is three times that of the slower ball.
In fact, I would use the word "difference" and not "change", since the balls are distinct.
Answered by
Anonymous
ok, thanks for your help
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