Asked by algebra

Given a right triangle whose side lengths are integral multiples of 7, how many units are in the smallest possible perimeter
Answered by Reiny
The smallest possible perimeter is obtained when we have the smallest possible sides.
But the sides are supposed to be multiples of 7
So they have to be 7 and 14
Hypotenuse^2 = 7^2 + 14^2
Hypotenuse = √245

so smallest possible perimter = 7+14+√245
= 21 + √245

Answered by Henry
21 + [(square root of 5) x 7]
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