Asked by Willard
Simplify: (Sin^2x)/(Sec^2x-1)
Answers
Answered by
helper
(sin^2 x)/(sec^2 x - 1)
(sin^2 x)/(tan^2 x)
(sin^2 x)/(sin^2 x/cos^2 x)
(sin^2 x) * (cos^2 x/sin^2 x)
cos^2 x
therefore,
(sin^2 x)/(sec^2 x - 1) = cos^2 x
(sin^2 x)/(tan^2 x)
(sin^2 x)/(sin^2 x/cos^2 x)
(sin^2 x) * (cos^2 x/sin^2 x)
cos^2 x
therefore,
(sin^2 x)/(sec^2 x - 1) = cos^2 x
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