Asked by Ricky
A Ferris Wheel, 24.0 m in diameter, rotates once every 12.5s. What is the fractional change in a person's apparent weight: a) at the top, and b) at the bottom?
I need to know if I'm doing this right. Here's my work:
Equation Used:
Net Force = [(4(pi)^2)(R)(M)] / [T^2]
M=mass
T=Period
R=Radius
FN= Normal Force
mg = weight
Top:
mg - FN = [(4(pi)^2)(R)(M)] / [T^2]
FN = (6.77M) Newtons
Bottom:
FN - mg = [(4(pi)^2)(R)(M)] / [T^2]
FN = (12.8M) Newtons
This is what I got so far, but I'm not sure what it means by the fractional change in a person's apparent weight. So where do I go from here?
I need to know if I'm doing this right. Here's my work:
Equation Used:
Net Force = [(4(pi)^2)(R)(M)] / [T^2]
M=mass
T=Period
R=Radius
FN= Normal Force
mg = weight
Top:
mg - FN = [(4(pi)^2)(R)(M)] / [T^2]
FN = (6.77M) Newtons
Bottom:
FN - mg = [(4(pi)^2)(R)(M)] / [T^2]
FN = (12.8M) Newtons
This is what I got so far, but I'm not sure what it means by the fractional change in a person's apparent weight. So where do I go from here?
Answers
Answered by
fqa
dad
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