Asked by Bebe
Fluorine-18, which has 1/2 life of 110 minutes, is used in PET scans. If 100 mg of fluorine-18 is shipped @8AM, how many milligrams of the radioisotope are still active if the sample arrives at the lab at 1:30 pm?
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
ln(No/N) = kt
No = 18 mg
N = unknown
k from above.
t = minutes from 8 am to 1:30 pm.
OR, to keep the numbers a little more workable, you may wish to use t</sub>1/2</sub> in hours (110/60), then use t = hours from 8:00 AM to 1/:30 pm.
ln(No/N) = kt
No = 18 mg
N = unknown
k from above.
t = minutes from 8 am to 1:30 pm.
OR, to keep the numbers a little more workable, you may wish to use t</sub>1/2</sub> in hours (110/60), then use t = hours from 8:00 AM to 1/:30 pm.
Answered by
Anonymous
0.50
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.