Asked by karla
What the solution of the equation: y^2-3y=9 ?
Answers
Answered by
helper
y^2-3y=9
y^2 - 3y = 9
complete the square
y^2 - 3y + 9/4 = 9 + 9/4
(y - 3/2)^2 = 45/4
+- (y - 3/2) = 45/4
solve for y
y = 3/2 (sqrt5 + 1)
y = -3/2 (-1 + sqrt5)
y^2 - 3y = 9
complete the square
y^2 - 3y + 9/4 = 9 + 9/4
(y - 3/2)^2 = 45/4
+- (y - 3/2) = 45/4
solve for y
y = 3/2 (sqrt5 + 1)
y = -3/2 (-1 + sqrt5)
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