Asked by TiffanyJ
Find each product or Quotient. Express using exponents.
1. The quotient of a to the 8th power and a to the 8th power? a
2. The quotient of -x to the 5th power and -x? -x to the 4th power
3. (15/5)(n to the 9th power/ n)? 3n go the 10th power
Neutral water has a pH of 7. Each one-unit decrease i the pH means that the solution is 10 times more acidic. How much more acidic vinegar is than baking soda if vinegar has a ph of 3 and baking soda has a ph of 9? I think the answer is 10 to the 6th power but I don't know how to write out my work.
1. The quotient of a to the 8th power and a to the 8th power? a
2. The quotient of -x to the 5th power and -x? -x to the 4th power
3. (15/5)(n to the 9th power/ n)? 3n go the 10th power
Neutral water has a pH of 7. Each one-unit decrease i the pH means that the solution is 10 times more acidic. How much more acidic vinegar is than baking soda if vinegar has a ph of 3 and baking soda has a ph of 9? I think the answer is 10 to the 6th power but I don't know how to write out my work.
Answers
Answered by
helper
if this is what you mean
1) a^8/a^8 = 1
2) -x^5/-x^4 = x
3) 15/5 * n^9/n = 3n^8
Also, use separate posts for 2 different questions/subjects
1) a^8/a^8 = 1
2) -x^5/-x^4 = x
3) 15/5 * n^9/n = 3n^8
Also, use separate posts for 2 different questions/subjects
Answered by
TiffanyJ
yes and sorry all the questions I asked are on the same homework paper
Answered by
helper
vinegar - pH 3
baking soda - pH 9
9 - 3 = 6 units diff.
10 x 6 = 60x as acidic
10^6 = 1 million, so I can't see how that is right
10^1.77815 = 60
I am not a tutor, so you might want to repost this as a separate question
baking soda - pH 9
9 - 3 = 6 units diff.
10 x 6 = 60x as acidic
10^6 = 1 million, so I can't see how that is right
10^1.77815 = 60
I am not a tutor, so you might want to repost this as a separate question
Answered by
TiffanyJ
Okay thank you
Answered by
helper
:) that's ok. also, you will have better response if posted separate.
Answered by
Anonymous
raise 8 to the 5th power, then find the quotient of the result and j
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