Asked by Zukii
lnx+ ln (x+3)= 2ln2
Answers
Answered by
Reiny
Using your laws of logs
ln[x(x+3)] = ln 2^2
x(x+3) = 4
x^2 + 3x - 4 = 0
it factors and solves easily , remember that for ln x to be defined, x > 0
ln[x(x+3)] = ln 2^2
x(x+3) = 4
x^2 + 3x - 4 = 0
it factors and solves easily , remember that for ln x to be defined, x > 0
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