Asked by Maria
The solubility of NaCl in water is 35.7 g NaCl/100 g H2O. Suppose that you have 500.0 g of NaCl. What is the minimum volume of water you would need to dissolve it all? The density of water is 1.0 g/mL.
Answers
Answered by
DrBob222
100 grams H2O x (500/37.5) = about 1330 mL. Or look at it this way.
37.5 g NaCl/100 mL = 0.375 g NaCl/1 mL.
So (0.375 g NaCl/mL) x ??mL = 500 g
Solve for ??mL.
37.5 g NaCl/100 mL = 0.375 g NaCl/1 mL.
So (0.375 g NaCl/mL) x ??mL = 500 g
Solve for ??mL.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.