Solve integration using u substitution of (x+1)sqrt(2-x)dx

Answer 1

integrate (x+1)sqrt(2-x)dx
u = (sqrt(2 - x))
u^2 = 2 - x
x = 2 - u^2
- 2u du = dx
I = integral sign

I (2 - u^2 + 1)u -2u du
I (3 - u^2)-2u^2 du
I (-6u^2 + 2u^4) du

-6 I u^2 du + 2 I u^4 du
2 I u^4 du - 6 I u^2 du

2 (1/5 u^5) - 6 (1/3 u^3)
2/5 u^5 - 2u^3

substitute back in for u = (sqrt(2-x))

2/5(sqrt(2-x))^5 - 2(sqrt(2-x))^3