a=Force/mass= mg/m=g
vf^2=vi^2+2ad
0=25^2+2*9.8 d solve for d.
time? Vf=vi-9.8 t solve for t.
if the greatest acceleration force which may be be applied to a vehicle is numerically equal to its weight, find a the least distance and b the least time, in which the vehicle travelling on a horizontal road can be brought to rest from an initial velocity of 25 m s-1
1 answer
1 answer