Asked by cecelia
given the following equation for a circle x^2-8x+y^2+4y+11=0 find its centre and radius
Answers
Answered by
Reiny
x^2-8x+y^2+4y+11=0
by completing the square...
x^2-8x+ <b>16</b> +y^2+4y+ <b>4 </b> = -11 + <b>16</b> + <b>4 </b>
(x-4)^2 + (y+2)^2 = 9
I am sure you can take it from here
by completing the square...
x^2-8x+ <b>16</b> +y^2+4y+ <b>4 </b> = -11 + <b>16</b> + <b>4 </b>
(x-4)^2 + (y+2)^2 = 9
I am sure you can take it from here
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