Question

a rectangle is 4 times as long as it is wide. a second rectangle is 5 centimeters longer and 2 centimeters wider than the first. the area of the second rectangle is 530 square centimeters greater than the first. what are the dimensions of the original rectangle?
L = 4 B
L2=L + 5
B2=B + 2

(L+5)(B+2) = LB +530
L B + 5B + 2 L + 10 = L B + 530

5 B + 2 L = 520
but L = 4 B
so
5 B + 8 B = 520
13 B = 530
B = 40.8
L = 163

LB = 6648
(L+5)(B+2) = 7174
difference = 525.6 pretty close
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