Asked by Raj

Alright, I've made a list of reactions that would produce precipatations.

NaCl + Zn
CaCl2 + NaOH
CaCl2 + Zn
CaCl2 + Na2SO4
CuSO4 + NaOH
CuSO4 + Zn
NaOH + AgNO3
NaOH + Zn
BaOH2 + AgNO3
BaOH2 + Zn
BaOH2 + Na2SO4

So this way I can figure if it is NaCl, CaCl2, CuSO4, NaOH,Ba(OH)2, HCl, HNO3, H2O.

First if its blue its CuSO4.
If it isn't, then I'd take the pH and if its acidic then its either HCl or HNO3. And I don't know how to differentiate between them though.

If its basic, its NaOH and Ba(OH)2, and I can use my percipitation reactions to eliminate which one it isn't The same for my neutral salts. If its water, it will be neutral and won't react with anything.

So does this procedure work better?
And how would i tell between HNO3 and HCl?
Answered by Raj
Wait, AgNO3 with any unknown with Cl present would form a precipatate. So I can use that to tell between HNO3 and HCl. So now is the whole thing correct?
Answered by DrBob222
NaCl + Zn <b> No reaction</b>
CaCl2 + NaOH <b>No reaction</b>
CaCl2 + Zn </b>No reaction</b>
CaCl2 + Na2SO4 <b>No reaction</b>
CuSO4 + NaOH <b>==>Cu(OH)2(solid, blue/white ppt + Na2SO4</b>
CuSO4 + Zn <b>==>ZnSO4 + Cu(solid) (The copper will plate out on the Zn metal. If the Zn metal is shiny, it will darken to almost black.</b>
NaOH + AgNO3 <b> ==> Ag2O(solid, black/brown ppt)</b>
NaOH + Zn<b>==> Zn(OH)2 (white gelatinous ppt)</b>
BaOH2 + AgNO3 <b> ==> Ag2O(solid black/brown ppt)</b>
Ba<b>(</b>OH<b>)</b>2 + Zn <b>==>Zn(OH)2<solid white gelatinous ppt.</b>
Ba<b>(</b>OH<b>)</b>2 + Na2SO4

So this way I can figure if it is NaCl, CaCl2, CuSO4, NaOH,Ba(OH)2, HCl, HNO3, H2O.

First if its blue its CuSO4. <b>OK</b>

If it isn't, then I'd take the pH and if its acidic then its either HCl or HNO3. And I don't know how to differentiate between them though.
<b>I would use litmus paper. It's faster and some of the other salts will give a pH that might confuse you as to the meaning. To diffferentiate between HCl and HNO3, use the chloride test. Add AgNO3, a white ppt is AgCl. The test solution, if it is HCl, should not be too strong; sometimes AgCl can form complex ions that are soluble (such as AgCl2^- or AgCl3^-2). I would take a portion of the sample, if it is acid to litmus paper, dilute it with deionized water (perhaps 1:5 or so), and add AgNO3 solution to it. HNO3 has no reaction to AgNO3.</b>

If its basic, its NaOH and <b>(OR, not and)</b> Ba(OH)2, and I can use my percipitation reactions to eliminate which one it isn't The same for my neutral salts. If its water, it will be neutral and won't react with anything.
<b>If it is NaOH or Ba(OH)2, I would test for Ba because that is so quickly done. Add SO4^-2 to NaOH or Ba(OH)2; the Ba solution fill form a white ppt of BaSO4 which is insoluble in acid.</b>

So does this procedure work better?
And how would i tell between HNO3 and HCl?
Answered by DrBob222
Ba(OH)2 + Na2SO4 <b>==> BaSO4(white ppt.)</b> + Na2SO4

Answered by DrBob222
Yes, AgCl is the way to go. See my other comments.
This procedure will help you determine some of the ions but it will not allow you to determine some of them.
Answered by Raj
About these:
NaCl + Zn No reaction
CaCl2 + NaOH No reaction
CaCl2 + Zn No reaction
CaCl2 + Na2SO4 No reaction

How would these give no reaction.
NaCl + Zn ==> ZnCl + Na
CaCl2 + NaOH ==> Ca(OH)2 + NaCl
CaCl2 + Zn ==> ZnCl + Ca
CaCl2 + Na2SO4 ==> CaSO4 + Na
Answered by DrBob222
CaCl2 + Na2SO4 No reaction <b>CaSO4 is not all that soluble so I might take this "no reaction" back. However, using AgNO3 to ppt AgCl still would be better.</b>

How would these give no reaction.
NaCl + Zn ==> ZnCl + Na <B> Zn is below Na in the EMF series; therefore, it will not replace Na in a single replacement reaction.</b>

CaCl2 + NaOH ==> Ca(OH)2 + NaCl <b> NaCl is soluble and Ca(OH)2, for all practical purposes, is soluble. At least it is soluble enough that this is not a good method for qualitative analysis.</b>

CaCl2 + Zn ==> ZnCl + Ca <b> Same comment as above. Zn is BELOW Ca in the EMF series (reactivity of metals); therefore, Zn will not replace Ca in a single replacement reaction.</b>

CaCl2 + Na2SO4 ==> CaSO4 + Na<b> See my comment above. CaSO4 is slightly soluble in water. It isn't a good test for qualitative analysis. </b>
Answered by Raj
Alright. Thank you so much for the help today.
Answered by Ali
CaCl2 + NaOH ---> Ca(OH)2 ppt
Answered by wnjr lqgahmx
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Answered by weslay
what is the name of ag2s in chemistry
Answered by Cook
You mean

Ba(OH)2 + Na2SO4 ==> BaSO4(white ppt.) + Na2(OH)2

NOT
Ba(OH)2 + Na2SO4 ==> BaSO4(white ppt.) + Na2SO4

Answered by Kelly
what about NaOH+NO ?
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