normal force on box: mg-25sin37
work done by rope: 25cos37*10+1/2 m(7^2-3^2) that is the work done by the pulling plus the change in KE.
I will be happy to critique your work.
1. A student is dragging a 5 kg box along the floor. He pulls on the rope with a 25 Newton force. The rope is 37 degrees above horizontal. As the box slides 10 meters, it goes from a speed of 3 m/s to a speed of 7 m/s.
a.) calculate the normal force on the box
b.) calculate the work the rope does on the box
c.) Calculate the box’s change in kinetic energy
d.) Calculate the work that friction does on the box.
e.) Calculate the force of friction on the box.
f.) Calculate the coefficient of sliding friction between the box and the floor.
g.) Calculate the student’s power.
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