well, consider the reverse: if she were going up at an initial velocity of 8.8 m/s, how high would she go in .93 sec?
h= 8.8*.93-1/2 g (.93^2)
The velocity of a diver just before hitting the water is -8.8 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 0.93 s of the dive?
1 answer