Vf^2 = Vo^2 + 2ad = 0,
(110)^2 + 2 * (-5.7)d = 0,
12100 - 11.4d = 0,
-11.4d = -12100,
d = -12100 / -11.4 = 1061.4m = 1.061km.
NO, the runway is too short
NOTE:Check your 1-11-11,7:44pm post.
A jet plane lands with a speed of 110 m/s and can decelerate uniformly at a maximum rate of 5.7m/s^2 as it comes to rest.
Can this plane land at an airport where the runway is 0.91 km long?
I have to answer by Calculating...HELP!
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