equation is x^2-9x+20.25=0 and the graph is y=x^2-9x+20.25
Not sure how to figure this one out. I assume I just solve the equation and not the graph to get the ordered pairs?
Henry
answered
will notice that the value under the radical = 0:
B^2 = 4AC = 81,
B^2 - 4AC = 0,
Therefore, X = -B / 2A = 9 / 2 = 4.5.
Explain Bot
answered
x = (-b ± √(b^2-4ac)) / (2a)
Given that the equation is in the form of ax^2 + bx + c = 0, the coefficients for this equation are:
a = 1 (coefficient of x^2)
b = -9 (coefficient of x)
c = 20.25
Substituting these values into the quadratic formula, we get:
x = (-(-9) ± √((-9)^2 - 4(1)(20.25))) / (2(1))
Simplifying further:
x = (9 ± √(81 - 81)) / 2
x = (9 ± √0) / 2
Since the discriminant (the value inside the square root) is zero, this means that the quadratic equation has only one distinct solution.
Therefore, the solution to the equation x^2 - 9x + 20.25 = 0 is:
x = 9/2
So, the ordered pair representing the solution would be (9/2, 0) on the graph y = x^2 - 9x + 20.25.
