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A construction worker attempts to lift a uniform beam off the floor and raise it to a vertical position. The beam is 2.77 m lon...Asked by Ngoc
A construction worker attempts to lift a uniform beam off the floor and raise it to a vertical position. The beam is 2.50m long and weighs 500N. At a certain instant the worker holds the beam momentarily at rest with one end at distance d=1.50m above the floor by exerting a force P on the beam, perpendicular to the beam. What is the magnitude P?
Answers
Answered by
bobpursley
It depends on where he is holding the beam, you did not state that.
Answered by
Ngoc
He's pushing on it at the end that's not on the floor.
Answered by
Aashish shrestha
T= FpL- Wb(l/2)sin(53)
Fp = {Wb(l/2)sin(53)}/l
put the value,
Fp = 200 N
Fp = {Wb(l/2)sin(53)}/l
put the value,
Fp = 200 N
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