see
http://www.jiskha.com/display.cgi?id=1294704010
Write the following expression as one logarithm: 2logx-log4-log3+logx.
Simplify your answer.
3 answers
That does not seem right to me because when i graph it, they turn out different.
I am using the 3 major laws of logs
logA + logB = log(AB)
logA - logB = log(A/B)
nlogA = log (A^n)
so again...
2logx-log4-log3+logx
= log(x^2) -log4-log3 + logx
= log((x^2)(x)/((3)(4))
= log (x^3/12)
You must be graphing it incorrrectly.
logA + logB = log(AB)
logA - logB = log(A/B)
nlogA = log (A^n)
so again...
2logx-log4-log3+logx
= log(x^2) -log4-log3 + logx
= log((x^2)(x)/((3)(4))
= log (x^3/12)
You must be graphing it incorrrectly.
1 answer