Question

A 14.0 kg cart is moving with a velocity of 7.25 m/s down a level hallway. A constant force of -10.0 N acts on the cart, and its velocity becomes 3.20 m/s. Assume that air resistance is negligible.
(a) What is the change in kinetic energy of the cart?
(b) How much work was done on the cart?
(c) How far did the cart move while the force acted?

Answer 1

final ke - initial ke = (1/2)14(3.2^2-7.25^2)

That is the work done

10 (distance) = work done