Asked by lets go
A 14.0 kg cart is moving with a velocity of 7.25 m/s down a level hallway. A constant force of -10.0 N acts on the cart, and its velocity becomes 3.20 m/s. Assume that air resistance is negligible.
(a) What is the change in kinetic energy of the cart?
(b) How much work was done on the cart?
(c) How far did the cart move while the force acted?
(a) What is the change in kinetic energy of the cart?
(b) How much work was done on the cart?
(c) How far did the cart move while the force acted?
Answers
Answered by
Damon
final ke - initial ke = (1/2)14(3.2^2-7.25^2)
That is the work done
10 (distance) = work done
That is the work done
10 (distance) = work done
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