Asked by michelle

A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 8000 N/C. The mass of the water drop is 3.54 10-9 kg
How many excess electrons or protons reside on the drop?
Answered by bobpursley
mg=Eq=E*e*n

n is the number of charges of e charge.
e is the fundamental charge on an electron.
solve for n

n= mg/Ee
Answered by michelle
((3.54 10-9 kg)(9.8))/ 8000 N/C
and it gave me the wrong answer so im not sure what im doing wrong.
Answered by drwls
What you have written does no thave the electron charge "e" in it.
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