Question

A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 8000 N/C. The mass of the water drop is 3.54 10-9 kg
How many excess electrons or protons reside on the drop?

Answers

bobpursley
mg=Eq=E*e*n

n is the number of charges of e charge.
e is the fundamental charge on an electron.
solve for n

n= mg/Ee
michelle
((3.54 10-9 kg)(9.8))/ 8000 N/C
and it gave me the wrong answer so im not sure what im doing wrong.
drwls
What you have written does no thave the electron charge "e" in it.

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