A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 8000 N/C. The mass of the water drop is 3.54 10-9 kg

How many excess electrons or protons reside on the drop?

3 answers

mg=Eq=E*e*n

n is the number of charges of e charge.
e is the fundamental charge on an electron.
solve for n

n= mg/Ee
((3.54 10-9 kg)(9.8))/ 8000 N/C
and it gave me the wrong answer so im not sure what im doing wrong.
What you have written does no thave the electron charge "e" in it.