Asked by Monte'
Solve each equation by completing the square.
-36x=8x^2+28
-8x^2-3x=-5
5x^2-x-6=0
6x^2-24x-30=0
7x^2+8x-12=0
-10x^2 -9x+1=0
5x^2-x=4
-11x^2-8x=-7x-10
-3 1/3x^2+ 10x -27 1/2= -231/3
-36x=8x^2+28
-8x^2-3x=-5
5x^2-x-6=0
6x^2-24x-30=0
7x^2+8x-12=0
-10x^2 -9x+1=0
5x^2-x=4
-11x^2-8x=-7x-10
-3 1/3x^2+ 10x -27 1/2= -231/3
Answers
Answered by
please help me...............paper due
#7) 5x^2-x=4 is x=1
Answered by
drwls
36x = 8x^2 +28
8 x^2 -36x +28 = 0
x^2- (9/2)x + 7/2 = 0
(x - 9/4)^2 +7/2 - 81/16 = 0
(x - 9/4)^2 = (81-56)/16 = 25/16
x - 9/4 = + or - 5/4
x = 1 or 7/2
I'll be glad to check your work on the other ones
8 x^2 -36x +28 = 0
x^2- (9/2)x + 7/2 = 0
(x - 9/4)^2 +7/2 - 81/16 = 0
(x - 9/4)^2 = (81-56)/16 = 25/16
x - 9/4 = + or - 5/4
x = 1 or 7/2
I'll be glad to check your work on the other ones
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