Heat energy required = Q
= (Mass)*(Specific Heat)*(Temperature rise)
It is often written M*C*(delta T)
For platinum, the answer is 5*25*133 = 17,000 J (rounded to two significant figures)
Now do water.
= (Mass)*(Specific Heat)*(Temperature rise)
It is often written M*C*(delta T)
For platinum, the answer is 5*25*133 = 17,000 J (rounded to two significant figures)
Now do water.
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius or Kelvin)
ΔT = change in temperature (in degrees Celsius or Kelvin)
Let's calculate the heat energy required to raise the temperature of the platinum block:
m = 5 kg (mass of the platinum block)
c = 133 J/kg*K (specific heat capacity of platinum)
ΔT = 25°C - 0°C = 25 K (change in temperature)
Q = 5 kg * 133 J/kg*K * 25 K = 16,625 J
Therefore, the amount of heat energy required to raise the temperature of the 5 kg block of solid platinum from 0°C to 25°C is 16,625 joules (J).
Now let's calculate the heat energy required to raise the temperature of 5 kg of water by the same amount:
m = 5 kg (mass of the water)
c = 4.2 kJ/kg*K (specific heat capacity of water)
ΔT = 25°C - 0°C = 25 K (change in temperature)
Since the specific heat capacity of water is given in kilojoules, we need to convert it to joules:
c = 4.2 kJ/kg*K * 1000 J/kJ = 4200 J/kg*K
Q = 5 kg * 4200 J/kg*K * 25 K = 525,000 J
Therefore, the amount of heat energy required to raise the temperature of 5 kg of water from 0°C to 25°C is 525,000 joules (J).