the prob of getting 12 when tossing 2 dice = 1/36
so the number expected doing this 1000 times
= 1000 x 1/36 = 250/9
= 27.777
so it would happen approx 28 times.
If you toss a pair of dice 1,000 times, how many times would you expect to get a sum of 12 as the result?
1.)about 12 times
2.)about 27 times
3.)about 36 times
4.)about 100 times
The lesson doesn't show me how to work this. Whats the formula?
4 answers
If you toss 3 coins 10,000 times, how many times would you expect that exactly 2 heads appear?
Tossing a die= 1/36 and so, the number expected of doing this 1000= 1/36 *1000=27.77777778 Approximately 28
36