Asked by Mathew
A line is perpendicular to x+3y-4=0 and has the same y-intercept as 2x+5y-20=0. Find an equation for the line
Answers
Answered by
drwls
Here are two hints:
(1) The first equation tells you that the slope of the line you are looking for is m = 3. That is because the line you want to be perpendicular to has a slope of -1/3.
(2) The y-intercept of the line you want is b = 20/5 = 4. The point is located at (0,4)
y = mx + b
Substitute in the m and b values from above.
(1) The first equation tells you that the slope of the line you are looking for is m = 3. That is because the line you want to be perpendicular to has a slope of -1/3.
(2) The y-intercept of the line you want is b = 20/5 = 4. The point is located at (0,4)
y = mx + b
Substitute in the m and b values from above.
Answered by
Anonymous
y=-1/3x+4
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