Asked by John

A line is parallel to 5x+2y-8=0 and has the same y-intercept as x+4y-12=0
Find an equation for the line.
Answered by Reiny
Since the new line is parallel to 5x + 2y - 8 = 0 , it must be
5x - 2y = c , that is, differing only in the constant

the y-intercept of the other line is (0,3), by mentally letting x = 0

sub in that point
5(0) + 2(3) = c , c = 6

new equation: 5x + 2y = 6 or 5x + 2y - 6 = 0
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