Asked by Tiara

A hiker shouts toward a vertical cliff 675 m away. The echo is heard 4.00 s later.

(a) What is the speed of sound of the hiker's voice in air? m/s
(b) The wavelength of the sound is 0.774 m. What is its frequency? Hz
(c) What is the period of the wave?

Answers

Answered by drwls
(a) It depends upon the air temperature. Usually about 340 m/s is used for the sound speed.

(b) frequency =
(sound wave speed)/(wavelength)
= 340/0.774
= ___ Hz

(c) Period = 1/(frequency)
(in seconds)
Answered by Tiara
thanks, you were right.
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