Asked by mota
I have a question in
(( distance between two points ))
show that A(4,2), B(-2,-2) and C(2,-8)are the vertices of an isoceles right triangle.
please in detales .. thank u
(( distance between two points ))
show that A(4,2), B(-2,-2) and C(2,-8)are the vertices of an isoceles right triangle.
please in detales .. thank u
Answers
Answered by
drwls
The lengths of the sides are
AB: sqrt(6^2 + 4^2) = sqrt 52 (side c)
BC: sqrt (4^2 + 6^2) = sqrt 52 (side a)
AC: sqrt (2^2 + 10^2) = sqrt 104 (side b)
This proves that two sides are equal and that it is a right triangle since
c^2 + a^2 = b^2.
AB: sqrt(6^2 + 4^2) = sqrt 52 (side c)
BC: sqrt (4^2 + 6^2) = sqrt 52 (side a)
AC: sqrt (2^2 + 10^2) = sqrt 104 (side b)
This proves that two sides are equal and that it is a right triangle since
c^2 + a^2 = b^2.
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