Asked by carly
what is the force excerted on the surface of a bowling ball that has a diameter of 32cm immersed in water to a depth of 555m?
Answers
Answered by
Damon
There is pressure all around the ball, pushing down on the top and up on the bottom and left on the right and right on the left.
However the problem asks for just one force, the vector resultant of all these forces.
That is the buoyant force up on the ball (Archimedes principle)
F buoyancy =rho g * volume
rho = 1000 kg/m^3
g = 9.8 m/s^2
volume = 4 pi r^3
where r = 0.32 meters
However the problem asks for just one force, the vector resultant of all these forces.
That is the buoyant force up on the ball (Archimedes principle)
F buoyancy =rho g * volume
rho = 1000 kg/m^3
g = 9.8 m/s^2
volume = 4 pi r^3
where r = 0.32 meters
Answered by
Damon
How about using just one name?
Answered by
Damon
volume = 4/3 * pi r^3
Answered by
carly
Actually i have some classmates over and were working together and we don't all have the same name. Sorry.
Answered by
carly
Sorry for sounding rude thank you for the help.
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