Asked by Anonymous

a ball is thrown at an initial angle of 37 and initail velocity of 23.0 m/s reaches a maximum height h, as shwon in the Figure. With what initial speed must a ball be thrown straight up to reach the same maximum height h?
Answered by bobpursley
Vi^2=2gh

Vi= sqrt (2gh)
Answered by Nayalin
sin(37) * 23 = 13.8
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