Asked by Anonymous
a ball is thrown at an initial angle of 37 and initail velocity of 23.0 m/s reaches a maximum height h, as shwon in the Figure. With what initial speed must a ball be thrown straight up to reach the same maximum height h?
Answers
Answered by
bobpursley
Vi^2=2gh
Vi= sqrt (2gh)
Vi= sqrt (2gh)
Answered by
Nayalin
sin(37) * 23 = 13.8
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