Question
help me please.
the perimeter of a rectangle is 120 inches. The length exceeds the width by 10 inches. Find the length and the width.
the perimeter of a rectangle is 120 inches. The length exceeds the width by 10 inches. Find the length and the width.
Answers
Ms. Sue
P = 2L + 2W
120 = 2(W + 10) + 2W
120 = 4W + 20
100 = 4W
? = W
120 = 2(W + 10) + 2W
120 = 4W + 20
100 = 4W
? = W
cindy
Hi Mrs. Sue... I'm still confused with the final answer. Can you make it more simple for me to understand. Thanks.
Ms. Sue
100/4 = 25
The width is 25.
The length is 25 + 10 = 35
120 = (2 * 25) + (2 * 35)
120 = 50 + 70
The width is 25.
The length is 25 + 10 = 35
120 = (2 * 25) + (2 * 35)
120 = 50 + 70