Asked by JessieLynne
If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the fround? Could someone help with the equation, please
Answers
Answered by
bobpursley
How long does it take to fall 40 m?
h= 1/2 g t^2
solve for t.
Now, given that time in the air, how far did the car travel horizontally?
distance= 15*t
h= 1/2 g t^2
solve for t.
Now, given that time in the air, how far did the car travel horizontally?
distance= 15*t
Answered by
JessieLynne
So I say:
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground
Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground
Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own
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