How long does it take to fall 40 m?
h= 1/2 g t^2
solve for t.
Now, given that time in the air, how far did the car travel horizontally?
distance= 15*t
If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the fround? Could someone help with the equation, please
2 answers
So I say:
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground
Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground
Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own
2 answers