Asked by lena

what is the slope of a line tangent to y=sin^2(5x+pi) at x=pi/4?

14 years ago

Answered by TutorCat

Take the derivative. Remember to apply the chain rule!

y'=[2sin(5x+pi)](5)

plug in pi/4

14 years ago

Answered by TutorCat

y'=[2sin(5x+pi)]*(cos(5x+pi))*5

14 years ago

Answered by TutorCat

look at example 3:

http://web.mit.edu/wwmath/calculus/differentiation/chain.html

14 years ago

Answered by lena

thank you

14 years ago

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