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what is the slope of a line tangent to y=sin^2(5x+pi) at x=pi/4?

4 answers

Take the derivative. Remember to apply the chain rule!

y'=[2sin(5x+pi)](5)

plug in pi/4

y'=[2sin(5x+pi)]*(cos(5x+pi))*5

look at example 3:

http://web.mit.edu/wwmath/calculus/differentiation/chain.html

thank you

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