Asked by juliet
find a number where the sum of itself and its cube is the same as twice the square if it
Answers
Answered by
Marth
Let x be the number.
"the sum of itself and its cube is the same as twice the square if it"
x+x^3 = 2x^2.
Solve by factoring
x^3-2x^2+x=0
x(x^2-2x+1)=0
x(x-1)^2=0
x = 0,1
"the sum of itself and its cube is the same as twice the square if it"
x+x^3 = 2x^2.
Solve by factoring
x^3-2x^2+x=0
x(x^2-2x+1)=0
x(x-1)^2=0
x = 0,1
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