can someone please help me.

Question

The perimeter of a rectangle is 80m. The length is 7m more than twice and width. Find the dimensions.

I would appreciate help with the steps so I can practice it for the my next problem. Thanks.

Answer 1

Let l be the length.
Let w be the width.

"The length is 7m more than twice and width."
l = 2w+7

The perimeter of a rectangle is P=2(l+w).
Substitute in l=2w+7 for the length.

80 = 2(2w+7+w)
80 = 2(3w+7)
80 = 6w + 14
66 = 6w
w = 11

l = 2w+7
l = 29

Answer 2

i dont know the answer