Asked by Jay
                Hi, I'm absolutely stuck on this problem. This is for a newton's method/linearization unit. Find an equation for the curve in the xy-plane that passes through the point (1,-1) if its slope at x is always 3x^2+2.
            
            
        Answers
                    Answered by
            Damon
            
    dy/dx = 3x^2+2
so
y = x^3 + 2 x + c
if x = 1, y = -1
-1 = 1 + 2 + c
c = -4
y = x^3 + 2 x - 4
    
so
y = x^3 + 2 x + c
if x = 1, y = -1
-1 = 1 + 2 + c
c = -4
y = x^3 + 2 x - 4
                    Answered by
            Damon
            
    I do not know why you would want to use Newton's Method.
    
                    Answered by
            Jay
            
    This was on a test I took earlier and I'm going back now to fix my mistakes. Thank you Damon-you've been a big help!
    
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