Asked by winston
If x2+xy=10, then when x=2, dy/dx=?
Answers
Answered by
Damon
2x dx + x dy + y dx = 0
x dy = -(2x+y) dy
dy/dx = - x/(2x+y)
when x = 2, y = (10-x^2)/x = 3
so
-2/(4+3) = -2/7
x dy = -(2x+y) dy
dy/dx = - x/(2x+y)
when x = 2, y = (10-x^2)/x = 3
so
-2/(4+3) = -2/7
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