Asked by chip
whats the vertex of 4y^2+4y-16x+13=0?
Answers
Answered by
Reiny
rearrange, then complete the square ....
16x = 4y^2 + 4y + 13
4x = y^2 + y <b>+ 1/4 - 1/4</b> + 13/4
4x = (y + 1/2)^2 -1/4 + 13/4
4x = (y+1/2)^2 - 3
x = (1/4)(y + 1/2)^2 - 3/4
can you read the vertex from that?
16x = 4y^2 + 4y + 13
4x = y^2 + y <b>+ 1/4 - 1/4</b> + 13/4
4x = (y + 1/2)^2 -1/4 + 13/4
4x = (y+1/2)^2 - 3
x = (1/4)(y + 1/2)^2 - 3/4
can you read the vertex from that?
Answered by
chip
so is it (-3/4,-1/2)?
Answered by
Reiny
yes, good for you to notice that you had to read the x and y in inverse form.
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