Asked by arthur
whats the center of the hyperola
25y^2-144x^2+150y-576x-3951=0
25y^2-144x^2+150y-576x-3951=0
Answers
Answered by
drwls
Complete the squares or the x and y binomials.
-(12x + 24)^2 +576 + (5y +15)^2 -225 -3951 = 0
-12(x+2)^2 +5(y+3)^2 = 3600
This can be written
-12 x'^2 + 5y'^2 = 3600
where x' = x+2 and y' = y+3
This is the equation of a hyperbola centered at x= -2, y = -3, where x' and y' are zero.
-(12x + 24)^2 +576 + (5y +15)^2 -225 -3951 = 0
-12(x+2)^2 +5(y+3)^2 = 3600
This can be written
-12 x'^2 + 5y'^2 = 3600
where x' = x+2 and y' = y+3
This is the equation of a hyperbola centered at x= -2, y = -3, where x' and y' are zero.
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