Asked by Cas
tan 30degrees = sin 60degrees /1+cos 60degrees
I pluged in the numebrs and i got this .
ã3/3= ã3/2 / 1+1/2
now i don't know how to work the problem to get the answer which is supposed to be ã3/3=ã3/3
i want an explaintion cuz i want to know how to do it.. and let me know if i pluged them wrong.
I pluged in the numebrs and i got this .
ã3/3= ã3/2 / 1+1/2
now i don't know how to work the problem to get the answer which is supposed to be ã3/3=ã3/3
i want an explaintion cuz i want to know how to do it.. and let me know if i pluged them wrong.
Answers
Answered by
Cas
ã is the square root sign i don't know why it changed .
Answered by
bobpursley
in the denominator, you have 1 1/2 which is 3/2
Answered by
Anonymous
okay still i end up with this
square root of 3/3 =square root of 3/2 / 3/2
??
square root of 3/3 =square root of 3/2 / 3/2
??
Answered by
Reiny
The right side
= (√3/2) / (1 + 1/2)
= √3/(2) / (3/2)
= (√3/2)(2/3_
= √3/2
= left side
= (√3/2) / (1 + 1/2)
= √3/(2) / (3/2)
= (√3/2)(2/3_
= √3/2
= left side
Answered by
Henry
tan30 = sin60 / (1 + cos60).
sqrt(3)/3 = sqrt(3)/2 / (1 + 1/2),
sqrt(3)/3 = sqrt(3)/2 / (3/2),
sqrt(3)/3=sqrt(3)/2 * 2/3, The 2 cancel
sqrt(3)/3 = sqrt(3)/3.
sqrt(3)/3 = sqrt(3)/2 / (1 + 1/2),
sqrt(3)/3 = sqrt(3)/2 / (3/2),
sqrt(3)/3=sqrt(3)/2 * 2/3, The 2 cancel
sqrt(3)/3 = sqrt(3)/3.
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