Asked by chem
An excess of aluminum metal is added to 200.0 mL of 0.025 M solution of CuCl2, reducing the Cu+2 ions to metallic Cu. If the temperature of the solution increases from 25.0 to 27.5 degrees celsius, what is the enthalpy of this reaction per mole of Cu formed? (Specific heat of solution = 4.18 J/gK)
a) 2.09 kJ
B) 23.0 kJ
C) 83.6 kJ
D) 418 kJ
I wrote out the equation:
3 CuCl2 + 2Al = 2AlCl3 + 3Cu
There are 0.005 moles of CuCl2 present, so that will result in 0.005 moles of Cu. I found the mass and plugged it into the q=mc(change in T) equation, but got an answer different from those above. Help? Thansk!
a) 2.09 kJ
B) 23.0 kJ
C) 83.6 kJ
D) 418 kJ
I wrote out the equation:
3 CuCl2 + 2Al = 2AlCl3 + 3Cu
There are 0.005 moles of CuCl2 present, so that will result in 0.005 moles of Cu. I found the mass and plugged it into the q=mc(change in T) equation, but got an answer different from those above. Help? Thansk!
Answers
Answered by
bobpursley
your heat: 200*4.18*2.5 J
heat per mole=your heat/(.005)
= about 2000/.005J=about 400kJ
work it accurately and see if D is correct.
heat per mole=your heat/(.005)
= about 2000/.005J=about 400kJ
work it accurately and see if D is correct.
Answered by
nisse
23.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.