Asked by Anonymous

The rate constant fo a particular reaction increases by a factor of 6.5 when the temperature is increased from 300.0K to 310.0K. Calculate the activation energy.
Answered by DrBob222
Use the Arrhenius equation. Assume a number for k1, then make k2 6.5 x k1.
Answered by Jamaka
Shouldn't the activation energy always stay the same, just the rate at which it is reached changes ? I may be wrong.