A human has a reasonable chance of surviving an automobile crash if the body's deceleration is no more than 30 "g's". (1 "g" is 9.8 m/s^2) Calculate the force the body would have withstand decelerating at this rate. What is the distance travelled if the car was initially travelling at 90 km/hr?

asked by Anonymous

17 years ago

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1 answer

F=ma

then, for the last part...
vf^2= vo^2 + 2a * d where a= -30g

solve for d.

answered by bobpursley

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Question

A human has a reasonable chance of surviving an automobile crash if the body's deceleration is no more than 30 "g's". (1 "g" is 9.8 m/s^2) Calculate the force the body would have withstand decelerating at this rate. What is the distance travelled if the car was initially travelling at 90 km/hr?

1 answer

F=ma

then, for the last part...
vf^2= vo^2 + 2a * d where a= -30g

solve for d.

bobpursley · Answer

F=ma then, for the last part... vf^2= vo^2 + 2a * d where a= -30g solve for d.