Asked by Alex
On a recent trip to a water park, you notice there is a new slide that you ride down a steep hill, then it carries you back up another ramp and shoots you into a pool. All the kids around you are saying that you leave the ramp at 50 m/s. If the initial height of the slide is 100 m/s and the ramp height is 10m do you really get projected into the air at 50m/s?
Answers
Answered by
Damon
you fall 100-10 = 90 meters
m g h = 90*9.8 m = about 900 m
(1/2) m v^2 = 900 m
v^2 = 1800
v = about 43 m/s so less than 50 but not terribly far off
m g h = 90*9.8 m = about 900 m
(1/2) m v^2 = 900 m
v^2 = 1800
v = about 43 m/s so less than 50 but not terribly far off
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