Asked by o.
how do you go about finding y-intercept and the slope for the equation -2y+3y=-21
Answers
Answered by
drwls
One of the y's in your equation should probably be an x. Please verify your typing.
Rewrite your equation (after correcting it) into y = mx + b form.
m will be the slope and b will be the y-intercept, where the straight line crosses the y axis.
Rewrite your equation (after correcting it) into y = mx + b form.
m will be the slope and b will be the y-intercept, where the straight line crosses the y axis.
Answered by
miyako
-2y+3y = -21
y(-2+3)= -21
y(1)= -21
y = -21 + (-1)
y = -21 - 1
y = -22
y(-2+3)= -21
y(1)= -21
y = -21 + (-1)
y = -21 - 1
y = -22
Answered by
drwls
miyako's answer is incorrect. If both terms on the left contain a y, then y = -21. You would have a horizontal line with zero slope.
I still believe one of your x's should be a y
I still believe one of your x's should be a y
Answered by
jamal
move the x1,y1,x2, and y2 sliders back and forth.which sliders affect the rise?
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