Asked by Anonymous
Two polygons are congruent and the perimeter of the first polygon is 38 cm. If the sides of the second polygon are consecutive integers (x, x+1, x+2, x+3, etc.), what value of x makes the polygons into congruent quadrilaterals? Use x as the smallest side.
Answers
Answered by
drwls
Congruent figures have the same perimeters.
Quadrilaterals have four sides.
The perimeters of both would be 4x + 6.
Since 4x = 6 = 38, x = 8.
The side lengths are 8, 9, 10, and 11.
I don't see why the bring a second quadrilateral into the discusion.
Quadrilaterals have four sides.
The perimeters of both would be 4x + 6.
Since 4x = 6 = 38, x = 8.
The side lengths are 8, 9, 10, and 11.
I don't see why the bring a second quadrilateral into the discusion.
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